Given that electron charges is so small, such laws work very well to describe electrostatics getting normal products
ANSWER: The principles your see like the you to definitely your quote implement just if the costs would be thought of as a continuous fluid that pass on alone out on any body, no matter how large, while having zero occurrence. However, an instance as if you determine, which have 5 too much electrons is in no way such as for instance a liquid and i create reckon that sets from 5-0 to 0-5 is the distribution over a period. In principle, the 5 electrons perform arrange themselves to make certain that for each and every are given that well away about almost every other cuatro as you are able to, however, around wouldn’t be an alternative such as for example shipment.
QUESTION: Could it be you’ll so you can suspend an electron thru electrostatic levitation for the an effective consistent magnetized occupation? Incase the latest current is actually diminished enough therefore the electrostatic force on the electron try below the fresh new force on account of the electron’s weight do this new electron up coming sense a ‘fall’ due in order to gravity?
I am asking this simply because I’m curious if place a positron from inside the an excellent consistent magnetic occupation (when you look at the vacuum pressure) and you will decreasing the voltage so you can a very quick worthy of to ensure that brand new electrostatic force is lower compared to the pounds create result in a beneficial positron to help you and additionally feel an excellent ‘fall’. While it did experience an autumn it may be ascertained if this do slip upwards or downward.
Of the inertial mass I am talking about the brand new proportion of one’s push your apply at https://datingranking.net/trans-dating/ they separated by its velocity, put simply the effectiveness are accelerated
I’m 17 yrs old plus in the uk about to studies physics during the university inside the september and you can was only interested in this since the our topics this current year are electricity phenomena and you may we discussed millikan’s oil miss check out and therefore seemed a comparable form of suspension system when the electrostatic push and you can force due to the law of gravity were balanced.
Now, it is known to help you over the top reliability that inertial bulk off an effective positron is equivalent to the fresh new inertial mass out of an electron
ANSWER: It is always nice to see young folks asking interesting questions. First, I need to correct one thing: everywhere you refer to a “magnetic field” you should say “electric field”; a magnetic field exerts no force on a charge at rest which is what you want to observe, la Millikan. (A more correct way, relativistically, to say this would be that they have equal momenta for equal speeds.) I believe it is true that nobody has ever “weighed” a positron by measuring the force it experiences in a gravitational field. But, if the gravitational mass were different from the inertial mass, this would fly in the face of the theory of general relativity. But, let’s talk about the feasibility of your experiment. The mass of an electron is about 10 -30 kg so its weight would be about 10 -29 N (taking g?10 m/s 2 ). The electron charge is about 1.6×10 -19 C and so the electric field required to levitate an electron would be 10 -29 /1.6×10 -19 ?6×10 -11 V/m. Suppose we use a parallel plate capacitor to create this field. The charge density ? on a plate with field E is about ?=?0E?10 -11 x6x10 -11 =6×10 -22 C/m 2 which would correspond to an electron density on the plates of about 6×10 -22 /1.6×10 -19 ?0.004 electrons/m 2 ! This would correspond to about one electron for every 250 square meters! That would not give a very uniform field would it? There is no such thing as a uniform surface charge density because charges in nature do not comprise a continuous fluid; so really tiny uniform fields are not possible. I did all that just for the fun of it, but there is an even more serious considerationthe earth itself has an electric field near the surface of typically 100 V/m pointing down, so an electron would be repelled upward. To do your experiment you would have to get rid of that field and I do not believe that it would be possible to be assured that you could make the residual field much less than your 6×10 -11 V/m. Back to the drawing board! Keep asking those hard and interesting questions, though, and good luck with your university studies.